C++ 编程:显示斐波那契数列
为了理解这个示例,你应该具备以下 C++ 编程 主题的知识:
斐波那契数列是一个系列,其中下一个项是前两项的和。斐波那契数列的前两项是 0 和 1。
斐波那契数列:0, 1, 1, 2, 3, 5, 8, 13, 21
示例 1:显示 n 个项的斐波那契数列
#include <iostream>
using namespace std;
int main() {
int n, t1 = 0, t2 = 1, nextTerm = 0;
cout << "Enter the number of terms: ";
cin >> n;
cout << "Fibonacci Series: ";
for (int i = 1; i <= n; ++i) {
// 打印前两个项。
if(i == 1) {
cout << t1 << ", ";
continue;
}
if(i == 2) {
cout << t2 << ", ";
continue;
}
nextTerm = t1 + t2;
t1 = t2;
t2 = nextTerm;
cout << nextTerm << ", ";
}
return 0;
}
输出
Enter the number of terms: 10
Fibonacci Series: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34,
示例 2:生成直到某个数为止的斐波那契数列程序
#include <iostream>
using namespace std;
int main() {
int t1 = 0, t2 = 1, nextTerm = 0, n;
cout << "Enter a positive number: ";
cin >> n;
// 显示前两个项,始终是 0 和 1
cout << "Fibonacci Series: " << t1 << ", " << t2 << ", ";
nextTerm = t1 + t2;
while(nextTerm <= n) {
cout << nextTerm << ", ";
t1 = t2;
t2 = nextTerm;
nextTerm = t1 + t2;
}
return 0;
}
输出
Enter a positive integer: 100
Fibonacci Series: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89,